Answer to Question #142302 in Physics for Sydney

Question #142302

A Force of 85.0 N is applied over a distance of 23.4 m to slide a 36.5 kg block across the floor. What is the velocity of the block after the force was applied?

Expert's answer

"W=Fs=0.5mv^2\\\\(85)(23.4)=0.5(36.5)v^2\\\\v=10.4\\frac{m}{s}"

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