Question

A Force of 85.0 N is applied over a distance of 23.4 m to slide a 36.5 kg block across the floor. What is the velocity of the block after the force was applied?

Answer 1

$$W=Fs=0.5mv^2\\(85)(23.4)=0.5(36.5)v^2\\v=10.4\frac{m}{s}$$