Question

Jill pushes a lawn mower at an angle of 45o measured from the horizontal. If she applies an average force of 98.5 N for a distance of 2.50 meters, how much work did she do on the lawn mower?

Answer 1

By the definition of the work done, we have:

$$W=Fscos\theta=98.5\ N\cdot 2.5\ m\cdot cos45^{\circ}=174.12\ J.$$

Answer:

$W=174.12\ J.$