Question

An axe that weighs 8.0 kg is used to strikes the log with a force of 400 N that comes to rest in 0.04
seconds. What is the magnitude of the impulse? How fast is the axe approach the log?

Answer 1

$$I=Ft=(400)(0.04)=16\ Ns$$

$$v=\frac{I}{m}=\frac{16}{8}=2.0\frac{m}{s}$$