Question #141129
a lorry starts from rest and moves eith a constant acceleration of 8ms-2 . compute its velocity and the distance travelled after 4s has ellapsed
1
Expert's answer
2020-10-30T13:19:36-0400

The distance travelled by a body with constant acceleration (and zero initial speed) is:


d=at22d = \dfrac{at^2}{2}

where a=8m/s2a = 8m/s^2 is its acceleration, t=4st = 4s is ellapsed time. Thus, obtain:


d=at22=8422=64md = \dfrac{at^2}{2} = \dfrac{8\cdot 4^2}{2} = 64m

The velocity is:


v=at=8m/s24s=32m/sv = at = 8m/s^2\cdot 4s = 32 m/s

Answer. 32 m/s, 64m.


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