Answer to Question #141059 in Physics for Aryan Patel

Question

A 7kg object is at the top of a 3m tall ramp.Due to friction it is only moving 5m/s at the bottom.Calculate efficiency

g=9.8

Answer 1

$$\eta=\frac{0.5mv^2}{mgh}\\\eta=\frac{0.5(5)^2}{(9.8)(3)}=0.43$$