Solution
For photon dispersion relation is given by
E=Ak
k is wave vector it's power s=1.
Then relation between energy and density of state is given by
D(E)∝Eds−1D(E) \propto E^{\frac{d}{s}-1}D(E)∝Esd−1
Here for photon
s=1 d=1
D(E)∝E11−1D(E) \propto E^{\frac{1}{1}-1}D(E)∝E11−1
D(E)∝E0D(E) \propto E^0D(E)∝E0
Means density of state is independent of energy.
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