The electric field inside a charged sphere is given by:
where "\\rho = 2.4\\times 10^{-6}C\/m^3" is the charge volume density, "k = 9\\times 10^9N\\cdot m^2\/C^2" is the constant. Thus, if "r = 5cm = 0.05m", obtain:
"E = \\dfrac{4}{3}\\rho kr = \\dfrac{4}{3} 2.4\\times 10^{-6}\\cdot 9\\times 10^9\\cdot 0.05 =1.44\\space V\/m"
Answer. 1.44 V/m.
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