Question #140403
The speed of light in ice is 2.3 X 10^8 m/s. What is the
refractive index of ice?
1
Expert's answer
2020-10-25T18:28:10-0400

By the definition of the refractive index we have:


n=cv,n=\dfrac{c}{v},

here, nn is the refractive index of ice, c=3108 msc=3\cdot 10^8\ \dfrac{m}{s} is the speed of light in a vacuum, v=2.3108 msv=2.3\cdot 10^8\ \dfrac{m}{s} is the speed of light in ice.

Then, we get:


n=cv=3108 ms2.3108 ms=1.304n=\dfrac{c}{v}=\dfrac{3\cdot 10^8\ \dfrac{m}{s}}{2.3\cdot 10^8\ \dfrac{m}{s}}=1.304

Answer:

n=1.304n=1.304


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