Question #140103
An object has a kinetic energy of 275 J and a momentum of magnitude 25.0 kg * m/s. Find the (a) speed and (b) mass of the object.
1
Expert's answer
2020-10-25T18:31:26-0400

a) Let's first write the formulas for the momentum and kinetic energy:


p=mv,p=mv,KE=12mv2.KE=\dfrac{1}{2}mv^2.

We can rewrite the formula for the kinetic energy as follows:


KE=12mv2=12pv.KE=\dfrac{1}{2}mv^2=\dfrac{1}{2}pv.

From this formula we can find the speed of the object:


v=2KEp=2275 J25.0 kgms=22.0 ms.v=\dfrac{2KE}{p}=\dfrac{2\cdot 275\ J}{25.0\ \dfrac{kgm}{s}}=22.0\ \dfrac{m}{s}.

b) Finally, from the first equation we can find the mass of the object:


m=pv=25.0 kgms22.0 ms=1.14 kg.m=\dfrac{p}{v}=\dfrac{25.0\ \dfrac{kgm}{s}}{22.0\ \dfrac{m}{s}}=1.14\ kg.

Answer:

a) v=22.0 ms.v=22.0\ \dfrac{m}{s}.

b) m=1.14 kg.m=1.14\ kg.


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