Question #138935
An upgrade thermometer attached to a centimeter-scale reads 13cm in pure melting ice and 38cm in steam at one atmospheric pressure.When the thermometer is placed in a certain freezing mixture it reads 11.5cm.When the thermometer is placed in pure boiling ethanoic acid it reads 42.5cm. What is the temperature of the freezing mixture?
1
Expert's answer
2020-10-19T13:20:59-0400
T=a+bX0=a+13b100=a+38b=13b+38b=25bb=4a=13(4)=52T=a+bX\\0=a+13b\\100=a+38b=-13b+38b=25b\to b=4\\a=-13(4)=-52

1)


Tfr=52+4(11.5)=6°CT_{fr}=-52+4(11.5)=-6\degree C

2)


Teth=52+4(42.5)=118°CT_{eth}=-52+4(42.5)=118\degree C


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