Answer to Question #138935 in Physics for Celina

Question

An upgrade thermometer attached to a centimeter-scale reads 13cm in pure melting ice and 38cm in steam at one atmospheric pressure.When the thermometer is placed in a certain freezing mixture it reads 11.5cm.When the thermometer is placed in pure boiling ethanoic acid it reads 42.5cm. What is the temperature of the freezing mixture?

Answer 1

$$T=a+bX\\0=a+13b\\100=a+38b=-13b+38b=25b\to b=4\\a=-13(4)=-52$$

1)

$$T_{fr}=-52+4(11.5)=-6\degree C$$

2)

$$T_{eth}=-52+4(42.5)=118\degree C$$