Question #138886

Q No. 1

The position of an object moving along an x axis is given by x = 3t - 4t^2 + t^3, where x is in meters and t in seconds. Find the position of the object at the following values of t: (a) 1 s, (b) 2 s, (c) 3 s, and (d) 4 s. (e) What is the object’s displacement between t = 0 and t = 4s? (f)

What is its average velocity for the time interval from t = 2 s to t = 4 s? (g) Graph x versus t for 0 ≤ t ≤4 s and indicate how the answer for (f) can be found on the graph


Question No. 2

A pilot flies horizontally at 1300 km/h, at height h = 35 m above initially level ground. However, at time t = 0, the pilot begins to fly over ground sloping upward at angle θ = 4.3° (Fig). If the pilot does not change the airplane’s heading, at what time t does the plane strike the ground?


1
Expert's answer
2020-10-19T13:23:38-0400

1)

a)


x=3(1)4(1)2+(1)3=0 mx = 3(1) - 4(1)^2 + (1)^3=0\ m

b)


x=3(2)4(2)2+(2)3=2 mx = 3(2) - 4(2)^2 + (2)^3=-2\ m

c)


x=3(3)4(3)2+(3)3=0 mx = 3(3) - 4(3)^2 + (3)^3=0\ m

d)


x=3(4)4(4)2+(4)3=12 mx = 3(4) - 4(4)^2 + (4)^3=12\ m

e)


s=120=12 ms=12-0=12\ m

f)


v=12(2)42=7msv=\frac{12-(-2)}{4-2}=7\frac{m}{s}

g)



It is the tan of angle between x-axis and line x(2)-x(4).


2)


tan4.3=hdtan4.3=hvt=35(3.6)1300tt=1.29 s\tan{4.3}=\frac{h}{d}\\\tan{4.3}=\frac{h}{vt}=\frac{35(3.6)}{1300t}\\t=1.29\ s


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