Question

A sprinter starts from rest, and reaches their top speed of 12 m/s in 3 seconds.
Part 1) What is the acceleration of the sprinter?
Part 2) What is the average velocity of the sprinter during those 3 seconds?
Part 3) How far did the sprinter travel during those 3 seconds?

Answer 1

1)

$$a=\frac{v}{t}=\frac{12}{3}=4\frac{m}{s^2}$$

2)

$$V_{av}=0.5(v_i+v_f)=0.5(0+12)=6\frac{m}{s}$$

3)

$$s=V_{av}t=(6)(3)=18\ m$$