Question

Resolve a force of 100 N into two components which lie on opposite sides of the force and each of which makes an angle of 300 with the force.

Answer 1

$$F_{1y}=F_{2y}=0.5F=0.5(100)=50\ N\\F_{1x}=-F_{2x}=\frac{F_{1y}}{\tan{30}}=\frac{50}{\tan{30}}=86.6\ N$$