Answer to Question #137691 in Physics for Shelia Nelson

Question

A bike is traveling at 7.4 m/s when it slows at a constant rate and comes to a stop after 3.4 seconds what is the bicycles acceleration?

Answer 1

By definition, the acceleration is:

$$a = \dfrac{v_{final} - v_{initial}}{t}$$

where $v_{final} = 0m/s$ is the final velocity of the bike (since it comes to rest), $v_{initial} = 7.4m/s$ is the intial velocity of the bike and $t = 3.4s$ is the time of motion. Thus, have:

$$a = \dfrac{v_{final} - v_{initial}}{t} = \dfrac{0m/s -7.4m/s}{3.4s} \approx 2.18m/s^2$$

Answer. 2.18 m/s^2.