Question #137663
a sphere of mass 0.5kg and diameter 1m rolls without slipping with a constant velocity of 5ms-1. calculate its total energy
1
Expert's answer
2020-10-12T07:48:16-0400

Express its kinetic energy of linear motion of its center of mass:


EL=mv22.E_L=\frac{mv^2}{2}.

Express its angular velocity in terms of linear velocity and radius:


ω=v/r.\omega=v/r.


Express the moment of inertia:


I=25mr2.I=\frac{2}{5}mr^2.

Express the kinetic energy of rotational motion:


ER=Iω22.E_R=\frac{I\omega^2}{2.}

The total energy of motion is


E=EL+ER, E=mv22+mr2v25r2=710mv2=8.75 J.E=E_L+E_R,\\\space\\ E=\frac{mv^2}{2}+\frac{mr^2v^2}{5r^2}=\frac{7}{10}mv^2=8.75\text{ J}.


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