Question

A vehicle accelerates from rest to 24.6m/s at a constant 1.98 m/s^2. What distance did the vehicle cover during this acceleration?

Answer 1

We can find the distance covered by the vehicle from the kinematic equation:

$$v_f^2 = v_i^2 + 2as,$$ $$s = \dfrac{v_f^2-v_i^2}{2a}=\dfrac{(24.6 \ \dfrac{m}{s})^2-(0 \ \dfrac{m}{s})^2}{2 \cdot 1.98 \ \dfrac{m}{s^2}} = 153 \ m.$$

Answer:

$s = 153 \ m.$