Question

A projectile is fired at an 18 degree angle with an initial velocity of 11.3m/s. How far fro its launch will it land assuming the ground is level?

Answer 1

The formula for the range of projectile:

$$d=\frac{v^2}{g}\sin{2\theta}\\d=\frac{11.3^2}{9.8}\sin{36}=7.66\ m$$