Answer to Question #137500 in Physics for Kj

Question #137500

A ball is kicked horizontally at 5 m/s from a cliff 50 m high. How far from the base of the cliff will the ball strike the ground?

Expert's answer

"h=gt^2\/2\\to t=\\sqrt{2h\/g}=\\sqrt{2\\cdot 50\/9.81}\\approx3.2(s)"

"s=vt=5\\cdot3.2=16(m)". Answer

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