Answer to Question #137500 in Physics for Kj

Question

A ball is kicked horizontally at 5 m/s from a cliff 50 m high. How far from the base of the cliff will the ball strike the ground?

Answer 1

$h=gt^2/2\to t=\sqrt{2h/g}=\sqrt{2\cdot 50/9.81}\approx3.2(s)$

$s=vt=5\cdot3.2=16(m)$. Answer