During the first 0.2s, before your reacted, the car had passed
d1=25m/s×0.2s=5m After you hit the brakes it decelerates in the following time before the full stop:
v0=att=av0 where v0=25m/s and a=9.5m/s2.
In this time the car passes the following distance:
d2=v0t−2at2=av02−2av02=2av02 Obtain:
d2=2av02=2⋅9.5252≈32.9m The full distance:
d=d1+d2=5+32.9=37.9m Answer. 37.9 m.
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