Answer to Question #136620 in Physics for Vanessa

Question #136620

a bullet moving horizontally to the right with a sped of 500m/s strikes a sandbag and penetrates a distance of 10cm. what is the average acceleration in m/s^2 of the bullet?

Expert's answer

"s=\\frac{v^2-v_0^2}{2a}\\to a=\\frac{v^2-v_0^2}{2s}=\\frac{0^2-500^2}{2\\cdot0.1}=1250000(m\/s^2)"

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