Question #136338
how fast is the collision crash of a 5,000kg car moving with a velocity of 5.2 m/s that hits a stationary 8,000kg truck on a frictionless track
1
Expert's answer
2020-10-05T10:56:32-0400

Assuming that the collision is purely inelastic, we can apply conservation of momentum:


mcvc+mtvt=(mt+mc)u, u=mcvc+mtvtmt+mc=50005.2+800005000+8000=2 m/s.m_cv_c+m_tv_t=(m_t+m_c)u,\\\space\\ u=\frac{m_cv_c+m_tv_t}{m_t+m_c}=\frac{5000\cdot5.2+8000\cdot0}{5000+8000}=2\text{ m/s}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS