For sound waves the intensity is defined as
"I=\\frac{1}{2}\\rho A^2\\omega ^2v" or "I=\\frac{(\\Delta p_0)^2}{2\\rho v}"
if "I_{1000}=I_{2000}" "\\to" "\\Delta p_{1000}=\\Delta p_{2000}".
Yes. The pressure amplitude of the 1000-Hz sound at the distance of 100m from the source is the same as that of the 2000-Hz sound at the same distance.
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