Answer to Question #135976 in Physics for Myrane

Question

A car initially traveled at a speed of 16 meters per second acceleration uniformly to a speed of 20 meters per second over a distance of 36 meters what is the acceleration

Answer 1

The acceleration is

$$a=\frac{v_f^2-v_i^2}{2d},\\\space\\ a=\frac{20^2-16^2}{2\cdot36}=2\text{ m/s}^2.$$