Answer to Question #135186 in Physics for Leanna Saleh

Question

A biker bikes 1450 meters uphill in 15 minutes. He averages 2.4 m/s for the entire 2720 meter portion of the trip. What is his average velocity on the way down the hill.

Answer 1

The average velocity is total distance divided by elapsed time:

$$v=2.4=\frac{D}{T}=\frac{2720}{15\text{ min}\cdot60\text{ s/min}+t_\text{down}},\\\space\\ t_\text{down}=233\text{ s}.$$

The average velocity down is

$$v_\text{down}=\frac{d_\text{down}}{t_\text{down}}=\frac{2720-1450}{233}=5.45\text{ m/s}.$$