Question #134846
An engine raises 100kg of water through a height of 60m in 20s what is the power of the engine? Take g as 10ms
1
Expert's answer
2020-09-24T11:07:27-0400

By the definition of the power we have:


P=Wt=Fht=mght,P = \dfrac{W}{t} = \dfrac{Fh}{t} = \dfrac{mgh}{t},P=100 kg10 ms260 m20 s=3103 W=3 kW.P = \dfrac{100 \ kg \cdot 10 \ \dfrac{m}{s^2} \cdot 60 \ m}{20 \ s} = 3 \cdot 10^3 \ W = 3 \ kW.

Answer:

P=3103 W=3 kW.P =3 \cdot 10^3 \ W = 3 \ kW.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Elizabeth kalu
16.07.22, 01:23

Great

LATEST TUTORIALS
APPROVED BY CLIENTS