Answer to Question #134132 in Physics for kim

Question

An object moving at 49 m/s was able to increase its velocity to 128 m/s within 8.44 seconds. What is the acceleration of the object?

Answer 1

We can find the acceleration of the object from the formula:

$$a = \dfrac{v-v_0}{t} = \dfrac{128 \ \dfrac{m}{s}-49 \ \dfrac{m}{s}}{8.44 \ s} = 9.36 \ \dfrac{m}{s^2}.$$

Answer:

$a = 9.36 \ \dfrac{m}{s^2}.$