To get the estimate of the actual speed, let us consider the case of initial speed, such that the truck stops just before the tree. The equations of motion are:
"v(t) = v_0 - a t", "S(t) = v_0 t - \\frac{a t^2}{2}".
The time it takes to stop is found from "v(t') = v_0 - a t' = 0", from where "t' = \\frac{v_0}{a}".
The displacement in that time is "S(t') = \\frac{v_0^2}{a} - \\frac{v_0^2}{2 a} = \\frac{v_0^2}{2 a}". Hence, given the length of skid marks "S = 43.4 m", from the last equation the initial speed it would take to completely stop in front of the tree is "v_0 = \\sqrt{2 S a} \\approx 23.75 \\frac{m}{s}". Since the truck ran into the tree, the speed must have been higher than "23.75 \\frac{m}{s}".
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