Velocity for an accelerated motion changes as "v(t) = v_0 + a t", where "v_0" is initial velocity, "a" is acceleration and "t" is time.
In our case, "v_0 = 0" (start from rest), hence "v(t) = a t". From the last formula, "a = \\frac{v(t)}{t} = \\frac{25 \\frac{km}{hr}{}}{80 s} = \\frac{25 \\frac{km}{hr}}{80\/3600 hr} = 1125 \\frac{km}{hr^2}"
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