Velocity for an accelerated motion changes as v(t)=v0+atv(t) = v_0 + a tv(t)=v0+at, where v0v_0v0 is initial velocity, aaa is acceleration and ttt is time.
In our case, v0=0v_0 = 0v0=0 (start from rest), hence v(t)=atv(t) = a tv(t)=at. From the last formula, a=v(t)t=25kmhr80s=25kmhr80/3600hr=1125kmhr2a = \frac{v(t)}{t} = \frac{25 \frac{km}{hr}{}}{80 s} = \frac{25 \frac{km}{hr}}{80/3600 hr} = 1125 \frac{km}{hr^2}a=tv(t)=80s25hrkm=80/3600hr25hrkm=1125hr2km
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