(2N−1)t=8(2N-1)t=8(2N−1)t=8 and (2N−1)gt22=20(2N-1)\frac{gt^2}{2}=20(2N−1)2gt2=20
We have
402N−1=g64(2N−1)2→N=6480g+0.5=\frac{40}{2N-1}=g\frac{64}{(2N-1)^2} \to N=\frac{64}{80}g+0.5=2N−140=g(2N−1)264→N=8064g+0.5=
=6480⋅9.81+0.5≈8.=\frac{64}{80}\cdot9.81+0.5 \approx8.=8064⋅9.81+0.5≈8.
So, N=8N=8N=8.
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