Question

Replace the three forces shown by an equivalent force-couple system at point A. If the forces are replaced by a single resultant force, determine the distance d below point A to its line of action.

Answer 1

(a) $300\cdot1.44-270\cdot0.72-210\cdot0.72=86.4(N\cdot m)$

The equivalent moment at point A $86.4(N\cdot m)$

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For force-couple

$F\cdot d=C\cdot l\to C=F/2=360/2=180(N)$ and

$l=2d=2\cdot0.24=0.48(m)$

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(b) The equivalent force $300+270-210=360(N)$

(c) The distance $86.4/360=0.24(m)$ below point A.