(a) "300\\cdot1.44-270\\cdot0.72-210\\cdot0.72=86.4(N\\cdot m)"
The equivalent moment at point A "86.4(N\\cdot m)"
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For force-couple
"F\\cdot d=C\\cdot l\\to C=F\/2=360\/2=180(N)" and
"l=2d=2\\cdot0.24=0.48(m)"
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(b) The equivalent force "300+270-210=360(N)"
(c) The distance "86.4\/360=0.24(m)" below point A.
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