Question #131804

In order to determine the height of a building, a student measures the angle of elevation of the top of the building from a point 25m away. The angle of elevation is found to be 50°. What is the height of the building if the eyes of the student are 1.2m above the ground?

Expert's answer

H=h+dtan⁡50H=1.2+25tan⁡50=31 mH=h+d\tan{50}\\H=1.2+25\tan{50}=31\ m


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