Question #131559
an electric power station is connected to a factory by two wires 2.5 km apart of the potential difference between two terminals of the wire at the station is 240 v and at the factory 220 v and the factory uses a current intensity 80 a
1
Expert's answer
2020-09-03T14:10:22-0400
ΔV=240220=20 VR=2080=0.25ΩRl=0.255000=5.0105Ωm1\Delta V=240-220=20\ V\\R=\frac{20}{80}=0.25\Omega \\\frac{R}{l}=\frac{0.25}{5000}=5.0\cdot 10^{-5}\Omega\cdot m^{-1}

A=ρlR=1.571085.0105=3.14104 m2A=\frac{\rho l}{R}=\frac{1.57\cdot 10^{-8}}{5.0\cdot 10^{-5}}=3.14\cdot 10^{-4}\ m^2

r=3.14104π=0.01 mr=\frac{\sqrt{3.14\cdot 10^{-4}}}{\pi}=0.01\ m


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