Question #131340
A car is moving with a constant velocity of 8 and then accelerates at a rate of 2 m/s/s for 3 seconds. Determine the displacement (in whole meters) of the car during its acceleration.
1
Expert's answer
2020-09-03T14:10:48-0400

The displacement of the car is given by the kinematic law:


d=v0t+at22d = v_0t + \dfrac{at^2}{2}

where v0=8m/sv_0 = 8m/s is the initial velocity, a=2m/s2a = 2m/s^2 is the acceleration rate and t=3st = 3s is time. Thus, obtain:


d=83+2322=33md = 8\cdot 3 + \dfrac{2\cdot 3^2}{2} = 33 m

Answer. 33 m.


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