Answer to Question #130859 in Physics for Zahirah

Question #130859

A length of copper of square cross section measuring 1.00mm by 1.00mm is stretched by a tension of 40N.What is the tensile stress in Pa?

Expert's answer

"P=\\frac{F}{A}\\\\P=\\frac{40}{0.001^2}=4.00\\cdot10^7\\ Pa"

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