Question #130734
A block of a material has a Volume of 20cm cube and a density of 2.5g/cm cube. It is suspended from a spring balance with half of the volume of the block immersed in water . What is the reading of the spring balance?
1
Expert's answer
2020-08-27T10:24:52-0400

m=Fg=m−0.5ρV=20⋅2.5−0.5⋅1⋅20=50−10=40(g)m=\frac{F}{g}=m-0.5\rho V=20\cdot2.5-0.5\cdot1\cdot20=50-10=40(g)


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wilson sunny
27.11.23, 22:27

Great

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