Question #130657
A person jogging on a track at a speed of 5 m/s for 12s will cover what distance
1
Expert's answer
2020-08-26T10:48:02-0400

The distance covered by a person

d=vt=5 m/s×12 s=60 md=vt=5\:\rm m/s\times 12\: s=60\: m

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