The horizontal component of the force exerted by the rope on the trunk
"F_x=F\\cos \\theta=400\\:\\rm N\\times \\cos 30^{\\circ}=346\\:\\rm N"The vertical component of the force exerted by the rope on the trunk
"F_y=F\\sin \\theta=400\\:\\rm N\\times \\sin 30^{\\circ}=200\\:\\rm N"
Comments
Leave a comment