Answer to Question #130580 in Physics for Bretzraei

Question #130580
Suppose the problem in Sample Problem 16.2 is projected at 24.5 m/s, 60° above the horizontal. Find the (a) time of flight, (b) range, and (c) maximum height.
1
Expert's answer
2020-08-25T11:13:08-0400

Given:

v0=24.5m/sv_0=24.5\:\rm m/s

θ=60\theta=60^{\circ}

g=9.8m/s2g=9.8\:\rm m/s^2

(a) the time of flight

t=2v0sinθg=2×24.5sin609.8=4.33st=\frac{2v_0\sin\theta}{g}=\frac{2\times 24.5\sin 60^{\circ}}{9.8}=4.33\:\rm s

(b) the range

R=v02sin2θg=24.52sin1209.8=53mR=\frac{v_0^2\sin2\theta}{g}=\frac{24.5^2\sin 120^{\circ}}{9.8}=53\:\rm m

(c) the maximum height

H=v02sin2θ2g=24.52sin2602×9.8=23mH=\frac{v_0^2\sin^2\theta}{2g}=\frac{24.5^2\sin^260^{\circ}}{2\times 9.8}=23\:\rm m

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