Question #130206
. A lake is 10 m deep and 1 km by 1 km in area. All the water goes over a waterfall of 300 m high. How much electrical energy is produced at 100% efficiency from this energy supply?
1
Expert's answer
2020-08-21T10:44:16-0400

The mass of water in a lake

m=ρV=1000kg/m3×10m×1000m×1000m=1010kgm=\rho V\\ =1000\:\rm kg/m^3\times 10\: m\times 1000\: m\times 1000\: m=10^{10}\: kg

The amount of energy

E=mgh=1010kg×9.8N/kg×300m=2.94×1013JE=mgh\\ =10^{10}\:\rm kg\times 9.8\: N/kg\times 300\: m=2.94\times 10^{13}\:\rm J

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