Answer to Question #129979 in Physics for nimra

Question

The time period of a simple pendulum is 2 s. What will be its length on the Earth?
-2 What will be its length on the Moon if g =g /6? where g = 10 m s .

Answer 1

On the Earth

$T=2\pi\sqrt{\frac{l}{g}}\to l=\frac{gT^2}{4\pi^2}=\frac{9.81\cdot2^2}{4\cdot3.14^2}\approx1(m)$

On the Moon

$T=2\pi\sqrt{\frac{l}{g}}\to l=\frac{gT^2}{4\pi^2}=$

$=\frac{(9.81/6)\cdot2^2}{4\cdot3.14^2}\approx0.166(m)$