"H\/V=0.4\\to H=0.4V"
"H=F"
"V-mg-2mg=0\\to V=3mg"
"H=0.4\\cdot3mg=1.2mg"
"-mg(L\/2)\\cos60\u00b0-2mgx\\cos60\u00b0+1.2mgL\\sin60\u00b0=0"
"-(L\/2)\\cos60\u00b0-2x\\cos60\u00b0+1.2L\\sin60\u00b0=0"
"-L\/4-x+1.039L=0\\to\\frac{x}{L}=0.789"
So,
"x\\approx79\\%" of "L".
Comments
Leave a comment