Assume that there is no friction.
"\\frac{mv^2}{2}=mgh\\to h=\\frac{v^2}{2g}=\\frac{5^2}{2\\cdot9.81}=1.27(m)"
In our case "h=2R=2\\cdot1=2(m)".
"2>1.27"
So, the ball can not reach the highest point of the circular track.
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