The friction force
Ff=μN=μmgcosαF_f=\mu N=\mu mg\cos\alphaFf=μN=μmgcosα
Assume that μ=0.3\mu=0.3μ=0.3 and PPP is the weight of the body. We get
a) Ff=μN=0.3⋅100=30(N)F_f=\mu N=0.3\cdot100=30(N)Ff=μN=0.3⋅100=30(N)
b) Ff=μN=0.3⋅0=0F_f=\mu N=0.3\cdot0=0Ff=μN=0.3⋅0=0
The force P required to start the motion up the incline from rest
P>mgsinα+FfP>mg\sin\alpha+F_fP>mgsinα+Ff
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