Question #128936
The three finalist in a contest are brought to the center of a large flat field. calculate the following displacements:
72.4 m, 32^o east of south
57.3 m, 36^o south of west
17.8 m straight south
What is the magnitude and direction of the resultant?
1
Expert's answer
2020-08-10T19:53:55-0400

A(x,y)=(72.4sin32°,72.4cos32°)=(38.4m,61.4m)A(x,y)=(72.4\sin32°,72.4\cos32°)=(38.4m,-61.4m)


B(x,y)=(57.3cos36°,57.3sin36°)=(46.4m,33.7m)B(x,y)=(57.3\cos36°,57.3\sin36°)=(-46.4m,-33.7m)


C(x,y)=(0m,17.8m)C(x,y)=(0m,-17.8m)


x=38.446.4=8m\sum{x}=38.4-46.4=-8m


y=61.433.717.8=112.9m\sum{y}=-61.4-33.7-17.8=-112.9m


Displacement=82+112.92=113.2(m)Displacement=\sqrt{8^2+112.9^2}=113.2(m)


Direction=tan1112.98=85.9°Direction=\tan^{-1}{\frac{112.9}{8}}=85.9° south of west.











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