Answer to Question #128904 in Physics for Preet Kaur Grover

Question #128904

.A person moves towards east for 3 m, then towards north for 4 m and then moves vertically up by 5 m. What is his distance now from the starting point?


1
Expert's answer
2020-08-10T19:54:03-0400


Using the Pythagorean theorem, from the right triangle AOB\triangle AOB express BOBO.

BO=32+42=5BO = \sqrt{3^2 + 4^2} = 5

Using the Pythagorean theorem again, from the right triangle BOC\triangle BOC express OCOC, which is the final distance from the starting point.


OC=CB2+BO2=52+52=52OC = \sqrt{CB^2 + BO^2} = \sqrt{5^2 + 5^2} = 5\sqrt2

Answer. 525\sqrt2.


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