Answer to Question #128788 in Physics for Precious Adeleye

Question #128788
What is the amount of heat generated during the freezing of m=10kg of water taken at temperature T=0°c.The heat of ice melting is 3.3×10⁴Jkg-¹
1
Expert's answer
2020-08-10T19:54:26-0400

The amount of heat generated during the freezing of water at temperature T=0°c can be calculated with the following formula:


Q=λmQ = \lambda m

where m=10kgm = 10 kg is the mass of water and λ=3.3×104J/kg\lambda = 3.3\times 10^4 J/kg is the heat of ice melting. Hence, obtain:


Q=λm=3.3×10410=3.3×105J=0.33×106J=0.33MJQ = \lambda m = 3.3\times 10^4\cdot 10 = 3.3\times 10^5J = 0.33\times 10^6J = 0.33MJ

Answer. 3.3×10^5 J or 0.33 MJ.


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