Question #128736
A car of mass 1000kg accelerates from rest for 90s in a straight line to reach a sped of 59km/h. After that, it accelerates uniformly at 6m/s^2 for a further 30s.

a) Calculate the speed of the car at the end of the 30s period.
b) Calculate the total distance covered by the car.
1
Expert's answer
2020-08-10T19:54:39-0400

(a)

vf=vi+atv_f=v_i+at

vf=59×1000m3600s+6m/s2×30s=196.4m/sv_f=59\times \frac{1000\:\rm m}{3600\:\rm s}+6\:\rm m/s^2\times 30\: s=196.4\:\rm m/s

(b)

d=d1+d2=0+59×1000m3600s2×90+59×1000m3600s+196.4m/s2×30=3929md=d_1+d_2\\ =\frac{0+59\times \frac{1000\:\rm m}{3600\:\rm s}}{2}\times 90+\frac{59\times \frac{1000\:\rm m}{3600\:\rm s}+196.4\:\rm m/s}{2}\times 30\\ =3929\:\rm m

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