Question

In isobaric process a gas did A=270J of work. By how much will the volume increase in this process, if gas pressure p=4.5×10⁴pa

Answer 1

In isobaric process the work a gas did can be expressed in the following way:

$$A = p\Delta V$$

where $\Delta V$ is the amount by which the volume will increase in this process and $p = 4.5\times 10^4 Pa$ is gas pressure. Expressing $\Delta V$, obtain:

$$\Delta V = \dfrac{A}{p} = \dfrac{270}{4.5\times 10^4} = 6\times 10^{-3} m^3$$

Answer. $6\times 10^{-3} m^3$.