Answer to Question #128362 in Physics for Alvin Vitale

Question

An airplane starting from rest takes 25 s and 500 m of runway at constant acceleration to leave the ground solve its velocity when it becomes airborne.

Answer 1

The distance traveled by an airplane

$d=\frac{v+v_0}{2}t$

Hence, the final velocity of an airplane

$v=\frac{2d}{t}-v_0=\frac{2\times 500\:\rm m}{25\:\rm s}-0\:\rm m/s=40\:\rm m/s$