Question

2. Compute for the Electric flux through an oval with a radius of 10m and has an electric field of 170N/C producing an angle θ=60. The electric flux is not parallel with surface and normal line.

Answer 1

By, definition, for a constant electric field, the flux will be:

$$\Phi = ES\cos\alpha$$

where $E = 170 N/C$ is the strengh of the electric field, $S = \pi r^2$ is the area of the oval, and $\alpha = 90\degree-\theta=30\degree$ is an angle between the electric field lines and the normal to $S$. Hence, obtain:

$$\Phi = ES\cos\alpha =170\cdot \pi\cdot 10^2 \cos30\degree \approx 46252\space NC^{-1}m^2$$

Answer. $46252\space NC^{-1}m^2$.